100% Prog JNTUK (29-1-24) SET 1-9a: Using pointers, print elements if array in reverse order

#include <stdio.h>
void main ()
{
  int i,arr[5],*ptr;
  ptr=&arr[0];
  for(i=0;i<5;i++)
  {
      printf ("\nenter element a[%d]:",i);
      scanf("%d",ptr+i);
  }
  printf("\n printing the numbers in reverse order begins:");
  while(i)
  {
      printf(" %2d",*(ptr+--i)); //ఈ లాజిక్ అవగతం చేసుకొనుట  కీలకం 
  }
 }

తెరమీద

enter element a[0]:1

enter element a[1]:3

enter element a[2]:5

enter element a[3]:7

enter element a[4]:9

 printing the numbers in reverse order begins:  9  7  5  3  1

-------------------------------------

#include <stdio.h>
void main ()
{
  int i,arr[5],*ptr;
  ptr=&arr[0];
  for(i=0;i<5;i++)
  {
      printf ("\nenter element a[%d]:",i);
      scanf("%d",ptr+i);
  }
 
  printf("\n printing the numbers in reverse order begins:");
  while(i)
  {
      printf(" %2d",*(ptr+--i));
  }
 
  printf("\n printing the numbers in actual order begins:");
  do
  {
    printf(" %2d",*(ptr+i++));
  }while(i<5);
 }

తెరమీద
enter element a[0]:1

enter element a[1]:3

enter element a[2]:5

enter element a[3]:8

enter element a[4]:2

 printing the numbers in reverse order begins:  2  8  5  3  1
 printing the numbers in actual order begins:  1  3  5  8  2