100% c sum of digits of number & printing number in reverse order

#include <stdio.h>

void main()

{

  int rem,numb,total=0,rev_total=0;  

 printf("\n enter a non-negative integer:");

 scanf("%d",&numb);

 while(numb)

 {

     rem=numb%10;

     total=total+rem;

     numb=numb/10;

     rev_total=rev_total*10+rem;

 }

    printf("\n sum of digits of given number =%d",total);

    printf("\n reverse of given number =%d",rev_total);

}

ఔట్పుట్  తెర  మీద ఇలా..

enter a non-negative integer:246
sum of digits of given number =12
 reverse of given number =642

enter a non-negative integer:0
sum of digits of given number =0
 reverse of given number =0

enter a non-negative integer:246

sum of digits of given number =12

 reverse of given number =642